# Line slope calculator x+2y=14

**Straight line given by points A[2; 6] and B[4; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.5x+7

**Canonical form of the line equation:**x+2y-14 = 0

**Parametric form of the line equation:**

x = 2t+2

y = -t+6 ; t ∈ R

**Slope:**m = -0.5

**Slope angle of line: φ =**-26°33'54″ = -0.4636 rad

**X intercept:**x

_{0}= 14

**Y intercept:**y

_{0}= q = 7

**Distance line from the origin:**d

_{0}= 6.261

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(2; -1)

**Normal vector: n =**(1; 2)

**Midpoint of the segment AB: M =**[3; 5.5]

**Perpendicular Bisector equation:**2x-y-0.5 = 0

**Vector OA = (2; 6) ; |OA| = 6.3246**

**Vector OB = (4; 5) ; |OB| = 6.4031**

**Scalar product OA .OB = 38**

**Angle ∠ AOB = 20°13'29″ = 0.353 rad**